In a cross between two heterozygous individuals (Ss x Ss), you can use a Punnett square to determine the expected genotypic ratio of the offspring.
The possible gametes from each parent are:
- From the first parent (Ss): S and s
- From the second parent (Ss): S and s
Setting up the Punnett square:
S s
----------------
S | SS | Ss |
----------------
s | Ss | ss |
----------------
From the Punnett square, the genotypes of the offspring are:
- 1 SS
- 2 Ss
- 1 ss
Therefore, the expected genotypic ratio is: 1SS : 2Ss : 1ss
So, the correct response is: 1SS: 2Ss: 1ss