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Question
In pea plants, wrinkled seeds (W) is the dominant trait, while smooth seeds (w) is the recessive trait. Consider the cross Ww X WW.

What will be the ratio of wrinkled to smooth seeds?
Responses
A 0:4 wrinkled:smooth0:4 wrinkled:smooth
B 2:2 wrinkled:smooth2:2 wrinkled:smooth
C 3:1 wrinkled:smooth3:1 wrinkled:smooth
D 4:0 wrinkled:smooth

Answer 1

To determine the genotype ratio from the cross Ww (heterozygous for wrinkled seeds) and WW (homozygous dominant for wrinkled seeds), we can use a Punnett square.

• The possible gametes from Ww are W and w.
• The possible gametes from WW are W and W.

Setting up the Punnett square:

        W      W
      ----------------
   W |  WW   |  WW   |
      ----------------
   w |  Ww   |  Ww   |
      ----------------

The offspring genotypes will be:

• WW (2 instances)
• Ww (2 instances)

All of the offspring (4 total) will exhibit the dominant trait (wrinkled seeds).

Therefore, the ratio of wrinkled (W) to smooth (w) seeds will be 4:0.

The correct answer is: D 4:0 wrinkled:smooth.