To find the maximum height of the apple, we can use the equations of motion.
The initial height of the apple is 2.00m and its initial speed is 15.5m/s. We need to determine the maximum height it reaches before falling back down.
The equation we can use is:
v^2 = u^2 + 2as
where:
v = final velocity (0 m/s at maximum height, as it momentarily stops before falling back down)
u = initial velocity (15.5 m/s)
a = acceleration (due to gravity, which is -9.8 m/s^2)
s = displacement (maximum height reached)
Rearranging the equation, we have:
0^2 = (15.5)^2 + 2(-9.8)s
0 = 240.25 - 19.6s
19.6s = 240.25
s = 240.25 / 19.6
s ≈ 12.27m
Therefore, the maximum height the apple reaches is approximately 12.27m.
in order to save time one worker decides to throw his apple up to his co-worker he releases the apple from a height of 2.00m above the ground level with an initial speed of 15.5m/s what is the maximum height of the apple
1 answer