Asked by bc
(x+3)/(x+8)-(x-8)/(x-3) I worked this out and got -55 Ans. But was marked wrong because the Ans. is 55 why and how does this end with no minus(-)sign please show working
Answers
Answered by
Steve
(x+3)/(x+8)-(x-8)/(x-3)
=[(x+3)(x-3) - (x-8)(x+8)]/[(x+8)(x-3)]
=[(x^2-9)-(x^2-64)]/[(x+8)(x-3)]
= (-9+64)/[(x+8)(x-3)]
= 55/[(x+8)(x-3)]
You probably forgot to use parentheses to keep track of quantities. But aside from that, what did you do with your denominator?
=[(x+3)(x-3) - (x-8)(x+8)]/[(x+8)(x-3)]
=[(x^2-9)-(x^2-64)]/[(x+8)(x-3)]
= (-9+64)/[(x+8)(x-3)]
= 55/[(x+8)(x-3)]
You probably forgot to use parentheses to keep track of quantities. But aside from that, what did you do with your denominator?
Answered by
bc
hey i know the answer now i wrote left to right instead of right to left and botched
the answer
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