Asked by Rachel
How would this problem be worked using dimensional analysis? Answer is 1.32g and I can work it (.900/13.6) * 20 = 1.32
But i need it in dimensional analysis and the hint was to first find volume of mercury.
How many grams of alcohol with a density of 0.900 g/cm3 will have the same volume as 20.0 g of mercury, with a density of 13.6 g/cm3?
But i need it in dimensional analysis and the hint was to first find volume of mercury.
How many grams of alcohol with a density of 0.900 g/cm3 will have the same volume as 20.0 g of mercury, with a density of 13.6 g/cm3?
Answers
Answered by
DrBob222
How about this? volume of Hg is mass/density or in dimensional analysis it is
20g x (1 cc/13.6 g) (g cancels and leaves cc which is volume) of Hg. .
Now we want to convert to grams alcohol.
20 g x (1 cc/13.6 g) x (0.9 g/cc) = ?
cc on top cancels with cc on bottom.
g on top cancels with grams on bottom and leaves a g on top.
20g x (1 cc/13.6 g) (g cancels and leaves cc which is volume) of Hg. .
Now we want to convert to grams alcohol.
20 g x (1 cc/13.6 g) x (0.9 g/cc) = ?
cc on top cancels with cc on bottom.
g on top cancels with grams on bottom and leaves a g on top.
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