In how many ways can 10 different books be divided among a, b and c so that 5 given to A, to 3 to B and 2 to C.

Answer 1

I don't suppose that the order of assigning the books matters so we have combinations.

"a" can be assigned books in C(10,5) ways, leaving 5 books for "b" who needs 3, that would be C(5,3), leaving the last 2 books to "c",

number of ways = C(10,5) x C(5,3) x C(2,2)
= 252*10*1
= 2520