down a frictionless slide: mg*SinTheta=ma
down a friction slide: mgSinTheta-mu*mg*CosTheta=ma
so if the time for friction is 2x, then its acceleration is half of the original a.
mgSinTheta-mu*mg*CosTheta=1/2 *(sinTheta)mg
solve for mu.
In Fig. 6-21, a slide-loving pig slides down a certain 37° slide in twice the time it would take to slide down a frictionless 37° slide. What is the coefficient of kinetic friction between the pig and the slide?
2 answers
0.377