a. 128
b.8 square root 2
c.16 square root 2
d.16
In △DEF, DF=16 and m∠F=45. Find the length of a leg. Leave your answer in simplest form.?
2 answers
If DF is the hypotenuse then DE = EF = 16/sqrt 2 = 16 sqrt 2 / 2
= 8 sqrt 2
If FE is the hypotenuse then FD=DE = 16
= 8 sqrt 2
If FE is the hypotenuse then FD=DE = 16