a) The final velocity of the two skaters is 4.00 m/s.
b) The kinetic energy lost is equal to the difference in the kinetic energies of the two skaters before and after the leap. The initial kinetic energy of the 65.0 kg skater is 0, and the initial kinetic energy of the 40.0 kg skater is 160 J. The final kinetic energy of the two skaters is 80 J. Therefore, the kinetic energy lost is 80 J.
In an ice show a 40.0 kg skater leaps into the air and is caught by an initially stationary 65.0 kg skater.
(a) What is their final velocity assuming negligible friction and that the leaper's original horizontal velocity was 4.00 m/s?
(b) How much kinetic energy is lost?
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