In an experiment, a seabird was taken from its nest, flown a distance 5190 km away, and released. It found its way back to its nest a time 13.8 days after release.
What was the bird's average velocity in m/s for the whole episode, from leaving the nest to returning?
Would I double the distance traveled?
2 answers
Although you could calculate the velocity for the return, there is no information to calculate the velocity for the trip from the nest. How fast did the plane fly?
The time given was the time spent away from the nest after release. We don't know the time spent away from the nest before it was released. I would not double the distance,because the bird did not fly away from the nest; it was
flown.
5190km * 1000m/km = 5,190,000m.
V=(5,190,000m / 13.8days)*(1/24)days /h
* (1/3600)h/s = 4.35m/s.
flown.
5190km * 1000m/km = 5,190,000m.
V=(5,190,000m / 13.8days)*(1/24)days /h
* (1/3600)h/s = 4.35m/s.
2 answers