In an emergency stop to avoid an accident,a shoulderstrap seat belt holds a 60-kg passenger firmly in place. If the car were initally traveling at 90 km/h and came to a stop in 5.5s along a straight, level road, what was the average force applied to the passenger by the seatbelt?

Answer 1

First convert 90 km/h to ___meters per second.
The conversion factor is
(1000 m/km) * (1 hr/3600s)
Divide that speed in m/s by 5.5 s to get the deceleration rate in m/s^2.

Mass(kg) x acceleration (m/s^2)
= Force (Newtons)

If you want it in pounds, multiply Newtons by 0.225 lb/N

Answer 2

272.7

Answer 3

2.7×10²