Question

in an emergency stop to avoid an accident, a shoulder-strap seat belt holds a 60kg passengr firmly in place. if the car was initially travelling at 90km/h and came to a stop in 4.5s along a straight, level road, what was the average force applied to the passenger by the seat belt? please help

Answer 1

Find the acceleration (deltaVeloicty/time)

Force=m*acceleration

Answer 2

so i converted my 90km/h to 25m/s, then found acceleration which was -5.56m/s^2.. i put that into F=m*a which was F=(60kg)(-5.56) F=-3336N or in significant digits -3000N.. is that correct?

Answer 3

55555577657374383284894270000000 N