Asked by nicky
a) a car does an emergency stop from 120000m/s in 3s. what was it's deceleration?
b) what was the car's average velocity and what was the stopping distance?
thank you
b) what was the car's average velocity and what was the stopping distance?
thank you
Answers
Answered by
Elena
v₀= 120000m/s??????????
v=v₀+at
v=0
(a) a= - v₀/t=
(b) v(ave) = (v+v₀)/2 = v₀/2
(c) s=v₀²/2a
v=v₀+at
v=0
(a) a= - v₀/t=
(b) v(ave) = (v+v₀)/2 = v₀/2
(c) s=v₀²/2a
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