|x-3|-|x-1|<0
|x-3| < |x-1|
I plotted |x-3| < |x-1|
www.wolframalpha.com/input/?i=%7Cx-3%7C+%3D+%7Cx-1%7C
from the graph we can see that x = 2 is the only solution for
|x-3| = |x-1|
so x > 2 is your solution for |x-3| < |x-1|
In absolute value
|x-3|-|x-1|<0
Find x
2 answers
makes sense, since |x-1| is the distance of x from 1.
same for |x-3|
Since 2 is the same distance (1) from 1 and 3, x>2 will be closer to 3 than to 1.
same for |x-3|
Since 2 is the same distance (1) from 1 and 3, x>2 will be closer to 3 than to 1.