In ΔABC, m∠ACB = 90°, and m∠ACD = 45°. Find:AC, if CD =6√2 in. can u put answer and solution

In ΔABC, m∠ACB = 90°, and m∠ACD = 45°. Find:AC, if CD =6√2

note that in a 45-45-90 right triangle, the sides are in the ratios 1:1:√2

So, draw the figure, label the known side, and then you can get the others.

so the answer is 6?

100% sure the answer isn't 6. Though I am struggling with this also, how do you find the sides when you only know the altitude?

Guys the altitude is equal to AD and DB.

thanks, now we have no idea what the answer is.

actually because we know its a 45 45 90 triangle, its an isosceles triangle so we can use base angle's theorem to figure out that AD=CD=6√2
then we can use the Pythagorean theorem to find that 6√2^2+6√2^2=12

still wrong

she forgot some of the question CD crosses over AB

Since CD and AC are both 6 x Square root of 2, AC would 12 because 6 Times Square root of 2 all to the power of 2 is 36 x2, which is 72, and 72 for both sides adds up to 144. Then you can find the square root of 144, so AC=12

Actually, if we can identify the perpendicularity, we can essentially see the physicality and rigorousness required to construct a powerful and proper solution that will satisfy the problem requirements. first, we need to construct an equilibrium and cancel out unnecessary factors. This problem is Quintessential of how we can use the Morgy Theorem to solve the problem.

Hope this helps!

The answer is 2.12

1.5 times square root of 2

2.12

ac=12

answer is : sq.rt. of 18/2

answer is 12

Im a monkey and i know it is 12 cmon yall the answer is 12

Its 12

Yes its 12

yup its def 12