In ∆ ABC, angle BAC= 68° and angle ABC =30°. BC is produced to X. The bisector of angle ABC and angle ACX meet at P. Calculate angle BCP and angle BPC

Answer 1

clearly the missing angle BCA = 82° leaving 98° for the exterior angle ACX
But that angle is bisected so angle ACP = 49°
giving us angle BCP = 131°

In triangle BPC we have 15° + 131 + angle BPC = 180
angle BPC = 34°

Answer 2

34

Answer 3

BCP =131 BPC=34