In a right triangle
given sides are
b=1 , c= root 10 ,a=?
a= root { 1^2 +(root 10)^2 }
= square root of 11
Because 1^2=1 & root 10^2=10
In a right triangle find the length of the side not given. b=1, c=sqrt10, a
need help
4 answers
So the third side is sqrt 11. I just want to make sure that I understand how to work this.
In a right triangle find the length of the side not given. b = 1, c = sqrt10, a = ?
If the two sides are a and b and the hypotensuse = c,
a^2 + b^2 = c^2
a^2 + 1^2 = 10
a^2 = 10 - 1 = 9 makaing a = sqrt9 = 3.
If the two sides are a and b and the hypotensuse = c,
a^2 + b^2 = c^2
a^2 + 1^2 = 10
a^2 = 10 - 1 = 9 makaing a = sqrt9 = 3.
Thanks for clearing that up