Question
find the value of x.
triangle xyz 2x, 4x+1, and 2x+3
perimeter of triangle xyz=88
triangle xyz 2x, 4x+1, and 2x+3
perimeter of triangle xyz=88
Answers
bobpursley
perimeter= sum of sides
88=2x + 4x+1 + 2x+3
solve for x.
88=2x + 4x+1 + 2x+3
solve for x.