Asked by mac
find the value of x.
triangle xyz 2x, 4x+1, and 2x+3
perimeter of triangle xyz=88
triangle xyz 2x, 4x+1, and 2x+3
perimeter of triangle xyz=88
Answers
Answered by
bobpursley
perimeter= sum of sides
88=2x + 4x+1 + 2x+3
solve for x.
88=2x + 4x+1 + 2x+3
solve for x.
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