In a reaction 3. 0 moles of CH4 was reacted with excess of CL2. 265g of CCL4 was obtained. calculate the theoretical yield and percentage yield of this reaction.

Answer 1

CH4 + 4Cl2 ==> CCl4 + 4HCl
How many moles CH4 did you have? That's 3.0 moles.
How much CCl4 will be formed? That's
3.0 mols CH4 x (1 mol CCl4/1 mol CH4) = 3.0 x 1/1 = 3.0 mols CCl4
grams CCl4 = mols CCl4 x molar mass CCl4 = 3.0 x 154 = 462 g CCl4 is the theoretical yield = TY. Actual yield = AY = 265 grams.
%yield = (AY/TY)*100 = ?