A student reacts 0.506 grams of aluminum with excess KOH and H2O according to reaction one from the lab manual.  

2Al + 2KOH +6H2O ---> 2K[Al(OH)4]+3H2

Enter your answers in numerical format.

How many moles of aluminum was reacted?

How many moles of K[Al(OH)4] will theoretically be produced?

1 answer

molar mass of Al is 27 g/mol

we used .506 g/27 g/mol
= .0187 mols of Al

for every mol of Al we get a mol of K[Al(OH)4]

so .0187