3CuSO4 + 2Al ==> Al2(SO4)3 + 3Cu
mols Al = grams/atomic mass
Using the coefficients in the balanced equation, convert mols Al to mols Al(SO4)3 produced.
Then g Al2(SO4)3 = mols x molar mass = ?
How many grams of aluminum sulfate are produced if 15.7 g Al reacts with excess CuSO4?
1 answer