In a population with two alleles, B and b, and the allele frequency of b is 0.4. Calculate the allele frequency of heterozygotes if the population is in Hardy–Weinberg equilibrium? Show your work.

Question

Thanks for any help in advance!

Answer 1

b=0.4

B+b=1, so

1-b=B

B=1-0.4=0.6

(B+b)^2=B^2+2Bb+b^2=1

(0.6)^2+[2(0.4)(0.6)]+(0.4)^2=1

Bb=heterozygous

Bb=2(0.4)(0.6)=0.48

But if you need to know,

BB=0.36
bb=0.16