In a population that is in Hardy–Weinberg equilibrium for two alleles, C and c, 16% of the population shows a recessive trait. Assuming C is dominant to c, state the percent of the population shows the dominant trait? Show your work.

Question

Thank you!

Answer 1

c=0.16

C+c=1, so

1-c=C

C=1-0.16=0.84

(C+c)^2=C^2+2Cc+c^2=1

(0.84)^2+[2(0.84)(0.16)]+(0.16)^2=1

Cc=Heterozygous dominant
Cc=2(0.84)(0.16)=0.27
CC=Homozygous dominant
CC=(0.84)^2=0.48

Frequency of CC + the frequency of Cc multiplied by 100 =percentage dominant for the trait

(0.27 +0.48)*100=75%

But if you need to know,

cc=0.25

or 25 % for the recessive trait.