In a parallelogram a diagonal of the length 20 cm is perpendicular to one of the sides. Find the longer side of parallelogram if its perimeter is 80 cm.

Answer 1

let long side = x
short side = s and is perpendicular to diag
s^2 + 400 = x^2
so s^2 = x^2 - 400
2 s + 2 x = 80
s = 40 - x
1600 - 80 x + x^2 = x^2 - 400
80 x = 2000
x = 200/8 = 100/4 = 25

Answer 2

I'm sorta Still cunflufled. /:

Answer 3

length=x
width=80-2x, 40-x
so using pythagorean theorem you get
(40-x)^2+(20)^2=x^2
1600-80x+x^2+400=x^2
-x^2. -x^2
1600+400-80x=0
2000-80x=0
-80x=-2000
x=25
so 25 is the width and 15 is the length

Answer 4

I need a picture. How is a diagonal perpendicular to a side?