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Suman
Questions (6)
An object of mass 10 kg 8s moving with a velocity of 6m/s. Calculate it's kinetic energy. If a constant opposite force.
1 answer
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Kevin will place point k at (1,2 1/2) on the grid below. Point k will be inside which type of triangle
1 answer
378 views
Rita and sita start jogging at the same point but in opposite directions.If the rate of one jogger is 2 mph faster than the
3 answers
1,422 views
Estimate Olympic swimming pool problem using Order of Magnitude Calculation:
An Olympic swimming pool is roughly 45 m long and 33
1 answer
901 views
A man moves 3.5m towards east then he moves 2m in south then 4.5m towards east. Find its distance and displacement.
2 answers
1,125 views
Using the dividend growth model and assuming a dividend growth rate of 5%, what is the rate of return for one of three key
0 answers
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Answers (12)
Show that any positive odd integer is of the form 6q+1,or 6q+3 or 6q+3 or 6q+5 where is some integer
length=x width=80-2x, 40-x so using pythagorean theorem you get (40-x)^2+(20)^2=x^2 1600-80x+x^2+400=x^2 -x^2. -x^2 1600+400-80x=0 2000-80x=0 -80x=-2000 x=25 so 25 is the width and 15 is the length
It is better to keep k value in exact form till you get final answer. So use k=ln(5/7) to find T(4). Also ln(5/7) can be written as -ln(7/5) using properties of logs T(4)=30+70e^(ln(7/5)*4) =48.2
Here we need to be careful while converting 0.2 m^3/min to cm ^3/min. Please note that 0.2 m^3 =0.2x10000000= 200000cm^3
V= W= Resultant =V+W Actual ground speed = magnitude of resultant = √(-136.87)^2+(336.04)^2 = 362.85 mph
Airplane velocity A=(325 cos110, 325 sin110) Wind velocity W=(40 cos130, 40 sin 130) resultant = A+W = Actual ground speed = √(-136.87)^2 +(336.04)^2 = 362.85 mph angle theta= arc tan (-336.04/136.87) = 112.16 bearing = 337.84
First step : Using distance formula, find the point lying on the line y= 1/2(x) with given distance = 3 ft. Find distance vector. Second step : Find Force vector in the direction of Third step : use formula W= Force * distance, get the work done in ft
(5x+70)/6 = x-4 x = 94
Humko samajh mai nhi aaya
1st girl 20 2nd girl 15 3rd girl 12 4rth girl 13
=1/3^3×3^2×4×7√2/5^2×(1/25)^1/3×1/3^4/3×1/5^4/3×3^1/3 =3^2×28√2×5^1/3×5^1/3×3^4/3×5^4/3/3^3×5^2×3^1/3 =28√2×3^2+4/3×5^1/3+1/3+4/3/3^3+1/3×5^2 =28√2×3^10/3×5^2/3^10/3×5^2 =28√2
A ball is thrown vertically upward with velocity 100ft/sec and height of building is 40ft what is maximum height reached by ball and what is velocity when ball hits the ground
