Suman

A man moves 3.5m towards east then he moves 2m in south then 4.5m towards east. Find its distance and displacement.

Estimate Olympic swimming pool problem using Order of Magnitude Calculation: An Olympic swimming pool is roughly 45 m long and 33 m wide. How long will it take to fill such a pool with an ordinary garden hose?

Rita and sita start jogging at the same point but in opposite directions.If the rate of one jogger is 2 mph faster than the other.After three hours,they are 30 miles apart,what is the rate of faster logger?

Kevin will place point k at (1,2 1/2) on the grid below. Point k will be inside which type of triangle

An object of mass 10 kg 8s moving with a velocity of 6m/s. Calculate it's kinetic energy. If a constant opposite force.

A ball is thrown vertically upward with velocity 100ft/sec and height of building is 40ft what is maximum height reached by ball and what is velocity when ball hits the ground

=1/3^3×3^2×4×7√2/5^2×(1/25)^1/3×1/3^4/3×1/5^4/3×3^1/3 =3^2×28√2×5^1/3×5^1/3×3^4/3×5^4/3/3^3×5^2×3^1/3 =28√2×3^2+4/3×5^1/3+1/3+4/3/3^3+1/3×5^2 =28√2×3^10/3×5^2/3^10/3×5^2 =28√2

1st girl 20 2nd girl 15 3rd girl 12 4rth girl 13

Humko samajh mai nhi aaya

(5x+70)/6 = x-4 x = 94

First step : Using distance formula, find the point lying on the line y= 1/2(x) with given distance = 3 ft. Find distance vector. Second step : Find Force vector in the direction of <2,3> Third step : use formula W= Force * distance, get the work done in...

Airplane velocity A=(325 cos110, 325 sin110) Wind velocity W=(40 cos130, 40 sin 130) resultant = A+W = <-136.87, 336.04> Actual ground speed = √(-136.87)^2 +(336.04)^2 = 362.85 mph angle theta= arc tan (-336.04/136.87) = 112.16 bearing = 337.84

V= <325 cos110, 325 sin110> W=<40cos130, 40sin130> Resultant =V+W Actual ground speed = magnitude of resultant = √(-136.87)^2+(336.04)^2 = 362.85 mph

Here we need to be careful while converting 0.2 m^3/min to cm ^3/min. Please note that 0.2 m^3 =0.2x10000000= 200000cm^3

It is better to keep k value in exact form till you get final answer. So use k=ln(5/7) to find T(4). Also ln(5/7) can be written as -ln(7/5) using properties of logs T(4)=30+70e^(ln(7/5)*4) =48.2

length=x width=80-2x, 40-x so using pythagorean theorem you get (40-x)^2+(20)^2=x^2 1600-80x+x^2+400=x^2 -x^2. -x^2 1600+400-80x=0 2000-80x=0 -80x=-2000 x=25 so 25 is the width and 15 is the length

Show that any positive odd integer is of the form 6q+1,or 6q+3 or 6q+3 or 6q+5 where is some integer