q needed to heat the water is
q = mass H2O x specific heat H2O x (Tfinal-Tinitial). Note that if you use specific heat listed you must change 110 kg H2O to grams.
1 lb x (? J needed/2.2E7 J/lb) = lbs oil needed. Convert to kg oil.
In a large building, oil is used in a steam boiler heating system. The combustion of 1.0 lb of oil provides 2.2×107J.
Part A
How many kilograms of oil are needed to heat 110 kg of water from 24 ∘C to 100∘C? (Assume that 1lb=454g, the specific heat of liquid water is 4.184 J/g∘C.)
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