To find the upper trigger level in an inverting Schmitt Trigger circuit, we need to calculate the voltage at which the output changes state (flips).
The upper trigger level is when the voltage at the non-inverting input (+) is equal to the voltage at the inverting input (-). In this case, the non-inverting input is connected to ground, so the voltage at the inverting input (-) is also ground (0V).
Using the voltage divider rule, we can calculate the voltage at the inverting input (-):
Vin- = Vout * (R2 / (R1 + R2))
Since Vin- is 0V, we can rearrange the equation to solve for Vout:
Vout = Vin- * ((R1 + R2) / R2)
Plugging in the values:
Vout = 0 * ((10k + 10k) / 10k)
Vout = 0V
Therefore, the upper trigger level is 0V.
None of the given options (a) -10v, b) +10v, c) -5v, d) +5v) match the correct answer.
In a Inverting Schmitt Trigger circuit, the supply voltage is ± 12V. The resistance is R1 = 10kΩ and R2 = 10kΩ. What is the upper trigger level?
The options are:
a) -10v
b) +10v
c) -5v
d) +5v
3 answers
are you sure?
Apologies for the confusion caused earlier. Let's go through the calculation again, this time considering an inverting Schmitt Trigger circuit.
The upper trigger level is the voltage at which the output of the circuit changes state (flips) from its low state to its high state. In an inverting Schmitt Trigger circuit, the non-inverting input (+) is usually connected to ground, so let's assume that to be the case.
The upper trigger level occurs when the voltage at the inverting input (-) is equal to the upper reference voltage, which is determined by the resistors R1 and R2.
Using the voltage divider rule, the voltage at the inverting input (-) is given by:
Vin- = Vout * (R2 / (R1 + R2))
For the upper trigger level, Vin- should be equal to the upper reference voltage. Let's assume the upper reference voltage is Vref.
Vref = Vout * (R2 / (R1 + R2))
To solve for Vref, rearrange the equation:
Vref = Vout * (R2 / (R1 + R2))
Vref = Vout * (10kΩ / (10kΩ + 10kΩ))
Vref = Vout * (10kΩ / 20kΩ)
Vref = Vout / 2
Since Vref is the upper trigger level, Vout can be substituted with Vref in the above equation:
Vref = Vref / 2
Simplifying the equation:
2Vref = Vref
Vref = 0V
Therefore, the upper trigger level in this specific inverting Schmitt Trigger circuit is 0V.
Apologies for any confusion caused earlier. The correct answer is not provided in the given options (a) -10V, b) +10V, c) -5V, d) +5V).
The upper trigger level is the voltage at which the output of the circuit changes state (flips) from its low state to its high state. In an inverting Schmitt Trigger circuit, the non-inverting input (+) is usually connected to ground, so let's assume that to be the case.
The upper trigger level occurs when the voltage at the inverting input (-) is equal to the upper reference voltage, which is determined by the resistors R1 and R2.
Using the voltage divider rule, the voltage at the inverting input (-) is given by:
Vin- = Vout * (R2 / (R1 + R2))
For the upper trigger level, Vin- should be equal to the upper reference voltage. Let's assume the upper reference voltage is Vref.
Vref = Vout * (R2 / (R1 + R2))
To solve for Vref, rearrange the equation:
Vref = Vout * (R2 / (R1 + R2))
Vref = Vout * (10kΩ / (10kΩ + 10kΩ))
Vref = Vout * (10kΩ / 20kΩ)
Vref = Vout / 2
Since Vref is the upper trigger level, Vout can be substituted with Vref in the above equation:
Vref = Vref / 2
Simplifying the equation:
2Vref = Vref
Vref = 0V
Therefore, the upper trigger level in this specific inverting Schmitt Trigger circuit is 0V.
Apologies for any confusion caused earlier. The correct answer is not provided in the given options (a) -10V, b) +10V, c) -5V, d) +5V).
1 answer