Asked by Anonymous

Determine ACL of Non-inverting amplifier.
RA = 500Ω
RB = 470Ω
RC = 20KΩ

VIN = 0.5Vp-p
Answered by Anonymous
I got 41 as ACL.
Answered by Anonymous
This is my answer:
acl = 1 + rf/ri
acl = 1 + 20000/500
acl = 41
Answered by Anonymous
Is this correct?
Answered by Anonymous
Determine ACL in dB
Answered by Anonymous
If the output saturation voltage of the op-amp is ± 8V, determine Voutpp.
Answered by Bot
The ACL (AC voltage gain) of a non-inverting amplifier is given by the following formula:

ACL = 1 + (RB/RA)

Substituting the given values, we get:

ACL = 1 + (470/500) = 1.94

Therefore, the ACL of the non-inverting amplifier is 1.94.

Note: The ACL is a dimensionless quantity and represents the ratio of output AC voltage to input AC voltage. It is also sometimes expressed in decibels (dB), which is given by 20log(ACL). In this case, the ACL in dB is 5.87dB.
Answered by Bot
The calculation for the ACL using the given values for the non-inverting amplifier is as follows:

ACL = 1 + (RB/RA) = 1 + (470Ω/500Ω) = 1 + 0.94 = 1.94

Therefore, the ACL of the non-inverting amplifier is 1.94 or approximately 1.9. It is possible that you made a calculation error or used different values for RA and RB. Please double-check your calculations and ensure that you are using the correct values.
Answered by Bot
If you use the given values of RA = 500Ω, RB = 470Ω, and RC = 20KΩ, the calculation for the ACL is as follows:

ACL = 1 + (RB/RA)
ACL = 1 + (470Ω/500Ω)
ACL = 1 + 0.94
ACL = 1.94

Therefore, the ACL of the non-inverting amplifier is 1.94 or approximately 1.9.

Your calculation seems to have used RC instead of RB in the formula, which would result in a different ACL value. Please double-check your calculation and ensure that you are using the correct values.
Answered by Bot
To determine the ACL in dB, we use the following formula:

ACL (dB) = 20 log10(ACL)

Substituting the calculated value of ACL = 1.94, we get:

ACL (dB) = 20 log10(1.94)
ACL (dB) = 20 × 0.287
ACL (dB) = 5.74 dB (approx)

Therefore, the ACL of the non-inverting amplifier in decibels is approximately 5.74 dB.
Answered by Bot
To determine Voutpp (the peak-to-peak output voltage), we need to consider the maximum and minimum possible output voltages of the amplifier.

Given that the output saturation voltage of the op-amp is ±8V, we know that the maximum and minimum output voltages of the amplifier are ±8V, respectively.

The peak-to-peak output voltage is then given by:

Voutpp = Vmax - Vmin

Substituting the values, we get:

Voutpp = (8V) - (-8V) = 16V

Therefore, the peak-to-peak output voltage of the amplifier would be 16V.