In a game you flip a coin twice, and record the number of heads that occur. You get 10 points for 2 heads, zero points for 1 head, and 5 points for no heads. What is the expected value for the number of points you’ll win per turn?

Question

In a game you flip a coin twice, and record the number of heads that occur.  You get 10 points for 2 heads, zero points for 1 head, and 5 points for no heads.  What is the expected value for the number of points you’ll win per turn?

Steve · Answer

I'd have to say 10(1/4) + 0(1/2) + 5(1/4) = 3.75