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In a game you flip a coin twice, and record the number of heads that occur. You get 10 points for 2 heads, zero points for 1 he...Asked by Kayla
In a game you flip a coin twice, and record the number of heads that occur. You get 10 points for 2 heads, zero points for 1 head, and 5 points for no heads. What is the expected value for the number of points you’ll win per turn?
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Answered by
Steve
I'd have to say
10(1/4) + 0(1/2) + 5(1/4) = 3.75
10(1/4) + 0(1/2) + 5(1/4) = 3.75
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