In a family with 4 children what is the probability of having 1 boy and then 3 girls, in that order? (Exclude multiple births and assume all outcomes are equally likely).

Question

In a family with 4 children, what is the probability of having 1 boy and 3 girls, in any order? (Exclude multiple births and assume all outcomes are equally likely).

Answer 1

your first part is
(1/2)(1/2)(1/2)(1/2)
= (1/2)^4
= 1/16

2nd part:
possible outcomes:
BGGG
GBGG
GGBG
GGGB , so 4 in all
each one has a prob of 1/16
so 4/16 or 1/4

Answer 2

In a family with 3 children what is the probability of having 1 boy and then 2 girls, in that order? (Exclude multiple births and assume all outcomes are equally likely).
In a family with 3 children, what is the probability of having 1 boy and 2 girls, in any order? (Exclude multiple births and assume all outcomes are equally likely).