In a dry cell, MnO2 occurs in a semisolid electrolyte paste and is reduced at the cathode. The MnO2 used in dry cells can itself be produced by an electrochemical process of which one half-reaction is shown below.

Mn2+(aq) + 2 H2O(l) MnO2(s) + 4 H+(aq) + 2 e -
If a current of 30.5 A is used, how many hours are needed to produce 1.10 kg of MnO2?

1 answer

I'm sure I worked this earlier. Let me know if there is something you don't understand about the process.