Question

In a closed system, three objects have the following momentums: 110 kg⋅m/s
, −65 kg⋅m/s
, and −100 kg⋅m/s
. The objects collide and move together. What is the total momentum after the collision?(1 point)
Responses

−275 kg⋅m/s
negative 275 kilograms times meters per second

55 kg⋅m/s
55 kilograms times meters per second

−55 kg⋅m/s
negative 55 kilograms times meters per second

275 kg⋅m/s

Answer 1

To find the total momentum after the collision, we need to add the momenta of the three objects together:

1. First momentum: \( 110 \, \text{kg⋅m/s} \)
2. Second momentum: \( -65 \, \text{kg⋅m/s} \)
3. Third momentum: \( -100 \, \text{kg⋅m/s} \)

Now, let's calculate the total momentum:

\[
\text{Total momentum} = 110 + (-65) + (-100)
\]
\[
= 110 - 65 - 100
\]
\[
= 110 - 165
\]
\[
= -55 \, \text{kg⋅m/s}
\]

Thus, the total momentum after the collision is \( -55 \, \text{kg⋅m/s} \).

The correct response is:
**−55 kg⋅m/s** (negative 55 kilograms times meters per second).