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In a closed system, an object with a mass of 1.5 kg collides with a second object. The two objects then move together at a velo...Asked by d
In a closed system, an object with a mass of 1.5 kg
collides with a second object. The two objects then move together at a velocity of 50 m/s
. The total momentum of the system is 250 kg⋅m/s
. What is the mass of the second object? (1 point)
Responses
3.5 kg
3.5 kg
5.0 kg
5.0 kg
1.5 kg
1.5 kg
3.0 kg
collides with a second object. The two objects then move together at a velocity of 50 m/s
. The total momentum of the system is 250 kg⋅m/s
. What is the mass of the second object? (1 point)
Responses
3.5 kg
3.5 kg
5.0 kg
5.0 kg
1.5 kg
1.5 kg
3.0 kg
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the mass of the second object, we can use the principle of conservation of momentum. The total momentum before the collision equals the total momentum after the collision.
Given:
- Mass of the first object, \( m_1 = 1.5 \, \text{kg} \)
- Final velocity of the combined objects, \( v_f = 50 \, \text{m/s} \)
- Total momentum of the system, \( p_{\text{total}} = 250 \, \text{kg} \cdot \text{m/s} \)
The momentum of the system after the collision can be expressed as:
\[
p_{\text{total}} = (m_1 + m_2) v_f
\]
where \( m_2 \) is the mass of the second object.
Substituting the known values into the equation:
\[
250 = (1.5 + m_2) \cdot 50
\]
Now, let's simplify and solve for \( m_2 \):
\[
250 = 50 \cdot (1.5 + m_2)
\]
Dividing both sides by 50:
\[
5 = 1.5 + m_2
\]
Subtracting 1.5 from both sides:
\[
m_2 = 5 - 1.5
\]
\[
m_2 = 3.5 \, \text{kg}
\]
Thus, the mass of the second object is **3.5 kg**.
Given:
- Mass of the first object, \( m_1 = 1.5 \, \text{kg} \)
- Final velocity of the combined objects, \( v_f = 50 \, \text{m/s} \)
- Total momentum of the system, \( p_{\text{total}} = 250 \, \text{kg} \cdot \text{m/s} \)
The momentum of the system after the collision can be expressed as:
\[
p_{\text{total}} = (m_1 + m_2) v_f
\]
where \( m_2 \) is the mass of the second object.
Substituting the known values into the equation:
\[
250 = (1.5 + m_2) \cdot 50
\]
Now, let's simplify and solve for \( m_2 \):
\[
250 = 50 \cdot (1.5 + m_2)
\]
Dividing both sides by 50:
\[
5 = 1.5 + m_2
\]
Subtracting 1.5 from both sides:
\[
m_2 = 5 - 1.5
\]
\[
m_2 = 3.5 \, \text{kg}
\]
Thus, the mass of the second object is **3.5 kg**.
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