To illustrate this information on a Venn diagram, we can start by drawing two circles to represent English and Math.
Inside the English circle, we write 46, representing the number of pupils who passed English. Inside the Math circle, we write 42, representing the number of pupils who passed Math.
Next, we need to include the information that each pupil passed at least one of the subjects. To do this, we draw an overlap section where the two circles intersect. Inside this overlap section, we write y, representing the number of pupils who passed both English and Math.
In the remaining parts of the circles outside the overlap section, we write the numbers of pupils who passed only English or only Math.
The completed Venn diagram would look like this:
English (46)
___________
/ \
/ \
/ \
/ \
/ \
(y) ______________ ______ (42)
English Only Math Only
To find the number of pupils who passed both subjects (y), we need to consider the total number of pupils in the class. In the Venn diagram, we have accounted for the pupils who passed only English (46 - y) and the pupils who passed only Math (42 - y).
According to the given information, each pupil passed at least one subject.
So, we can set up an equation using the total number of pupils in the class:
60 = (46 - y) + (42 - y) + y
Simplifying this equation, we get:
60 = 46 + 42 - y
Combining like terms:
60 = 88 - y
Rearranging to solve for y:
y = 88 - 60
y = 28
Therefore, 28 pupils passed both English and Math.
In a class of 60 pupils, 46 passed English and 42 passed math. Each pupil passed at least one of the subjects. I) illustrate this information on a van diagram. ii) how many pupils passed both subjects? Let's y represent the number of pupils who passed both subjects
1 answer
1 answer