37% passed algebra,
21% passed both, so
(37-21)=16% passed only algebra.
Similarly,
(29-21)=8% passed only English.
With these numbers, you should have no difficulties calculating the probabilities that you forgot to post.
A professor knows that in her class 37% of the students have passed an Algebra course, 29% have passed an English course, and 21% have passed both courses. If one student is selected at random from this class, find the probability that:
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