In a certain shipment of 14 phones, 8 are defective. 10 of the phones are selected at random without replacement. What is the probability that 5 of the 10 phones are defective?

Question

I'm not sure how I would go about doing this?

Answer 1

Prob(phone is defective) = 8/14 = 4/7
so prob(not defective) = 3/7

Prob(5 of 10 are defective) = C(10,5)(4/7)^5 (3/7)^5
= 252(1024/16807)(243/16807) = .....

This question falls in the category of
Binomial Distribution Probability