number(basket AND baseball) = Number(basket) + Number(baseball) - number(basket OR baseball)
= 14 + 10 - (30-14)
= 8
Verify this result with a Venn diagram, it is valid
prob(play both) = 8/30 = 4/15
In a certain Algebra 2 class of 30 students, 14 of them play basketball and 10 of them play baseball. There are 14 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
1 answer