In a bag, there are two types of candy bars: Snickers and Twix. Two items are chosen at random from the bag, without replacement. The probability of selecting a Snickers on the first draw is 71%. The probability of selecting a Snickers and then a Twix is 47%. What is the probability of selecting a Twix on the second draw, given that the first was a Snickers?

Question

mathhelper · Accepted Answer

let the prob of picking a Twix be p, then (.71)(p) = .47 p = .47/.71 = 47/71 = approx. .6619.. or about 66%