In a bag there are 2 red marbles 3 white marbles and 5 blue marbles. Once a marbel is picked it is not replaced. Find the following probabilities:

Question

P(red,then white)

P(blue, then red)

P(red, red, red)

P(blue, blue, white)

Answer 1

all are basically the same. The total number of marbles drops after each selection. For example,

P(blue, blue,white) = 5/10 * 4/9 * 3/8

Answer 2

But how would you solve the other 3 then

Answer 3

for each draw, it is the number of that color, divided by the total number of marbles. For more than one draw, just multiply the fractions.

Take a look at what I did. It should become clear.

Answer 4

I still don't understand.

Answer 5

Look. If there are 12 balls, and 5 are red, the chance of getting a red ball is 5/12.

After you have drawn that red ball, there are only 4 reds and 11 balls, so the chance of getting a 2nd red is 4/11

and so on.

Answer 6

That makes 0 sense there’s 10 balls not 12 just say the answer