15t = 5
t = 0.333h = 20 min.
11.6t = 5
t = 0.431h = 26 min.
T = 26 - 20 = 6 min. waiting time.
In a 5.00km race, one runner runs at a steady 11.6km/h and another runs at 15.0km/h. How long does the faster runner have to wait at the finish line to see the slower runner cross?
1 answer