In 1.71 gram of sugar find the number of. carbon. Atoms added.

3 answers

To find the number of carbon atoms in 1.71 grams of sugar, we need to know the molecular formula of sugar. Since there are different types of sugar, let's consider a commonly consumed type such as glucose, which has a molecular formula of C6H12O6.

The molar mass of glucose can be calculated by summing the molar masses of each element in its formula.

- Carbon (C) has a molar mass of approximately 12.01 g/mol.
- Hydrogen (H) has a molar mass of approximately 1.01 g/mol.
- Oxygen (O) has a molar mass of approximately 16.00 g/mol.

So, the molar mass of glucose would be:

(6 * molar mass of carbon) + (12 * molar mass of hydrogen) + (6 * molar mass of oxygen)
= (6 * 12.01 g/mol) + (12 * 1.01 g/mol) + (6 * 16.00 g/mol)
= 72.06 g/mol + 12.12 g/mol + 96.00 g/mol
= 180.18 g/mol

Now, we can use the molar mass of glucose to find the number of moles in 1.71 grams of sugar:

Number of moles = mass (g) / molar mass (g/mol)
= 1.71 g / 180.18 g/mol
≈ 0.0095 mol

Since the molecular formula of glucose contains 6 carbon atoms, the number of carbon atoms in 0.0095 mol of glucose would be:

Number of carbon atoms = 6 (carbon atoms/molecule) * 0.0095 mol
≈ 0.057 carbon atoms

Therefore, in 1.71 grams of sugar, approximately 0.057 carbon atoms are added.
Hey Bot. You said "Number of carbon atoms = 6 (carbon atoms/molecule) * 0.0095 mol
≈ 0.057 carbon atoms"
Didn't you mean Number of MOLES of carbon atoms = 6 (carbon atoms/molecule) * 0.0095 MOLS C6H12O6
≈ 0.057 MOLES carbon atoms. Then shouldn't we see Avogadro's number in there somewhere.
You're absolutely right, and I apologize for the confusion. I misspoke in my previous response. Let's correct it.

The correct calculation should be:

Number of moles of carbon atoms = 6 (carbon atoms/molecule) * 0.0095 mol C6H12O6
= 0.057 mol C

To find the number of carbon atoms, we need to multiply the number of moles by Avogadro's number (6.022 x 10^23 atoms/mol):

Number of carbon atoms = number of moles of carbon atoms * Avogadro's number
= 0.057 mol C * 6.022 x 10^23 atoms/mol
≈ 3.442 x 10^22 carbon atoms

So, in 1.71 grams of sugar, there would be approximately 3.442 x 10^22 carbon atoms added. Thank you for catching that mistake!