To find the number of carbon atoms in 1.71 grams of sugar (C12H22O11), we need to first calculate the molar mass of sugar.
The molar mass of C12H22O11 can be calculated by adding up the atomic masses of carbon (C), hydrogen (H), and oxygen (O):
(12.01 g/mol)(12) + (1.01 g/mol)(22) + (16.00 g/mol)(11) = 342.34 g/mol
Now, we can use the molar mass to determine the number of moles of sugar in 1.71 grams:
1.71 g / 342.34 g/mol = 0.004999 mol
Since there are 12 carbon atoms in one molecule of sugar, to find the number of carbon atoms in 0.004999 mol of sugar, we multiply the number of moles by Avogadro's number (6.022 x 10^23 atoms/mol):
0.004999 mol * (6.022 x 10^23 atoms/mol) = 3.01 x 10^21 carbon atoms
Therefore, in 1.71 grams of sugar, there are 3.01 x 10^21 carbon atoms.
In 1.71 gram of sugar (C12H22O11) find the number of. carbon. Atoms added.
3 answers
Bot I don't see where you corrected for the 12 C atoms in sucrose.
Apologies for the oversight. Let's correct it.
In each molecule of sugar (C12H22O11), there are 12 carbon atoms (C) present.
To find the number of carbon atoms in 1.71 grams of sugar (C12H22O11), we can use the molar mass and Avogadro's number.
The molar mass of C12H22O11 is calculated as follows:
(12.01 g/mol)(12) + (1.01 g/mol)(22) + (16.00 g/mol)(11) = 342.34 g/mol
Now, we can calculate the number of moles of sugar in 1.71 grams:
1.71 g / 342.34 g/mol = 0.004999 mol
Since each mole of sugar contains 12 carbon atoms, we can multiply the number of moles by the number of carbon atoms per mole:
0.004999 mol * 12 = 0.06 moles of carbon atoms
Finally, using Avogadro's number (6.022 x 10^23 atoms/mol), we can calculate the number of carbon atoms:
0.06 moles * (6.022 x 10^23 atoms/mol) = 3.61 x 10^22 carbon atoms
Therefore, in 1.71 grams of sugar, there are approximately 3.61 x 10^22 carbon atoms.
In each molecule of sugar (C12H22O11), there are 12 carbon atoms (C) present.
To find the number of carbon atoms in 1.71 grams of sugar (C12H22O11), we can use the molar mass and Avogadro's number.
The molar mass of C12H22O11 is calculated as follows:
(12.01 g/mol)(12) + (1.01 g/mol)(22) + (16.00 g/mol)(11) = 342.34 g/mol
Now, we can calculate the number of moles of sugar in 1.71 grams:
1.71 g / 342.34 g/mol = 0.004999 mol
Since each mole of sugar contains 12 carbon atoms, we can multiply the number of moles by the number of carbon atoms per mole:
0.004999 mol * 12 = 0.06 moles of carbon atoms
Finally, using Avogadro's number (6.022 x 10^23 atoms/mol), we can calculate the number of carbon atoms:
0.06 moles * (6.022 x 10^23 atoms/mol) = 3.61 x 10^22 carbon atoms
Therefore, in 1.71 grams of sugar, there are approximately 3.61 x 10^22 carbon atoms.