Imagine a landing craft approaching the surface of the moon of a distant planet. If the engine provides an upward force (thrust) of 2890 N, the craft descends at constant speed; if the engine provides only 2200 N, the craft accelerates downward at 0.36 m/s2.

Answer 1

m g = 2890

m g - 2200 = m (.36)

You did not say what your question is but
you can solve that for m and for the local g