Vo = 18.7m/s[51o]
Xo = 18.7*Cos51 = 11.8 m/s.
Yo = 18.7*sin51 = 14.5 m/s.
Y^2 = Yo^2 + 2g*h = 0
h = -Yo^2/2g = -14.5^2/-19.6 = 10.8 m.
Y^2 = Yo^2 + 2g*d = 0 + 19.6*(10.8-2.5)= 162.68
Y = 12.8 m/s = Ver. component.
V^2 = Xo^2 + Y^2 = 11.8^2 + 12.8^2 = 303.08
V = 17.4 m/s. = Speed just before landing.
I'm working on projectile motion and I am supposed to find the speed for this problem, however I'm having trouble setting up the problem. I'm not finding any help from the book either.
A golfer hits a shot to a green that is elevated 2.50 m above the point where the ball is struck. The ball leaves the club at a speed of 18.7 m/s at an angle of 51.0˚ above the horizontal. It rises to its maximum height and then falls down to the green. Ignoring air resistance, find the speed of the ball just before it lands.
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1 answer