I don't get the same number but close.
The atomic mass I used was 35.4527 which I rounded to 35.453; then,
35.453 x (3.01 x 10^23/6.02 x 10^23) = 35.453 x (1/2) = 17.7265 which rounds to 17.7 g to three significant figures.
I'm sooooooo not sure if I'm doing this right, but can someone check it please? Thanks :))
5) Determine the mass in grams of 3.01 x 10^23 atoms of Cl (element)
I got 17.5 grams...is this right?
2 answers
Oh okay thank you very much! :D