sqrt 2 is the legs of a 45,45, 90 triangle, hypotenuse is 2
sqrt 3 is the side opposite the 60 degree angle in a 30,60, 90 triangle. (legs are 1 and sqrt 3, hypotenuse is 2)
Learn those right triangles by heart. They come up constantly.
im really stuck on these, can anyone help me and also explain how to solve them:
Find the exact values of s in the given intervals that have the given circular function values.
1. [pi/2, pi]; sin s=sqrt2/2
2. [pi/2, pi]; cos s=-sqrt3/2
thnks:)
2 answers
how does that help me find s though..