Asked by y912f
im really stuck on these, can anyone help me and also explain how to solve them:
Find the exact values of s in the given intervals that have the given circular function values.
1. [pi/2, pi]; sin s=sqrt2/2
2. [pi/2, pi]; cos s=-sqrt3/2
thnks:)
Find the exact values of s in the given intervals that have the given circular function values.
1. [pi/2, pi]; sin s=sqrt2/2
2. [pi/2, pi]; cos s=-sqrt3/2
thnks:)
Answers
Answered by
Damon
sqrt 2 is the legs of a 45,45, 90 triangle, hypotenuse is 2
sqrt 3 is the side opposite the 60 degree angle in a 30,60, 90 triangle. (legs are 1 and sqrt 3, hypotenuse is 2)
Learn those right triangles by heart. They come up constantly.
sqrt 3 is the side opposite the 60 degree angle in a 30,60, 90 triangle. (legs are 1 and sqrt 3, hypotenuse is 2)
Learn those right triangles by heart. They come up constantly.
Answered by
y912f
how does that help me find s though..
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.