I'm not sure how to solve this equation algebraically:

Question

38=20sin((2pi(t))/36)+22

I know the answer should be about 5.3 since I graphed it.

I can get as far as removing 22 from the right and then removing 20 from the right by dividing by 20. To get 0.8=sin((2pi(t))/36)

Answer 1

PI*t/18=arcsin.8

t=18/PI * arcsin(.8)

Your calculator is needed on that.

Answer 2

thanks!