Im in Chem. but looks like physics.. If a rock climber accidentally drops a 70.5 g piton from a height of 295 meters, what would its speed be just before striking the ground? Ignore the effects of air resistance.

Answer 1

Do you have answers. If you checked my last answer and it was right you can look at this one.
X = distance = Vo*t + 1/2*g*t^2
Vo is 0 and the mass of the pick (piton) doesn't matter. X = 295 m, solve for t = time to strike the ground. Then use
V = Vo + g*t. Again, Vo is 0.