x f(x)
0 1
1 e
2 e^4
So, if there are 2 rectangles of width 1, then the area, using left-sides is
1*1 + 1*e = e+1 = 3.718
using right-sides, it's
1*e + 1*e^4 = 57.316
Using the trapezoidal rule, we have
1(1+e)/2 + 1(e+e^4)/2 = 30.517
Kind of a coarse approximation.
I'm a little confused with this integration problem: If the definite integral from 0 to 2 of (e^(x^2)) is first approximated by using two inscribed rectangles of equal width and then approximated by using the trapezoidal rule with n=2, the difference between the two approximations is what?
5 answers
Thank you!
Steve's answer is unfortunately incorrect. 30.517 was wrong when picked.
The answer is 26.80
Steve is correct. He gave us both the LH & RH approximations as well as the trapezoid approximation
You just needed to subtract Trapezoid & the LH which gives 30.517-3.718 = 26.80
You just needed to subtract Trapezoid & the LH which gives 30.517-3.718 = 26.80