Rasheda

I'm a little confused with this integration problem: If the definite integral from 0 to 2 of (e^(x^2)) is first approximated by using two inscribed rectangles of equal width and then approximated by using the trapezoidal rule with n=2, the difference betw...

A particle starts at the point (5,0) at t=0 and moves along the x-axis in such a way that at time t>0 its velocity v(t) is given by v(t)= t/(1+t^2). a). Determine the maximum velocity of the particle. Justify your answer. b). Determine the position of the...

Thank you!

So you have (8^6)/((8^4)*(8^2)). I would start with the denominator. When you are multiplying exponents with the same base, you add the exponents. So the above equation becomes (8^6)/(8^6). This simplifies to 1. For the second problem, it's slightly diffe...

Whenever you have a number raised to a negative power, you have to divide it. So 6y^-3 becomes (6)/(y^3)

1. The first thing you need to do is convert 60km to meters, or 10,000m to kilometers; whichever you prefer. Next,it helps if you draw a right triangle. The plane is at a height of 10,000m; this is the vertical leg of the triangle. It is 60 km away from t...

a). 4^(-1) is the same as 1/4. Since this is the diameter, you divided it by the 2 to get the radius. So the radius is 1/8. Now the expression is: A= pi*(1/8)^2 or A=(1/64)*pi b). In part a, the expression is for the area of one punched hole. Since you ha...